What are the solutions to the equation 12a^2-22a-5=-5a ?

The solutions to the equation 12a^2-22a-5=-5a are a= 5/3 ,a=-1/4

Find the zeros of 12a^2-22a-5=-5a

The zeros of 12a^2-22a-5=-5a are a= 5/3 ,a=-1/4

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12 a^{2} - 22 a - 5 = - 5 a

a = \frac{5}{3}, a = - \frac{1}{4}

Decimal Notation

a = 1.66666 \dots, a = - 0.25

Solution steps

12 a^{2} - 22 a - 5 = - 5 a

Move

5 a

to the left side

12 a^{2} - 17 a - 5 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 12 ( - 5 )}{2 \cdot 12}

(- 17)^{2} - 4 \cdot 12 (- 5) = 23

a_{1, 2} = \frac{- ( - 17 ) \pm 23}{2 \cdot 12}

Separate the solutions

a_{1} = \frac{- ( - 17 ) + 23}{2 \cdot 12}, a_{2} = \frac{- ( - 17 ) - 23}{2 \cdot 12}

a = \frac{- ( - 17 ) + 23}{2 \cdot 12} : \frac{5}{3}

a = \frac{- ( - 17 ) - 23}{2 \cdot 12} : - \frac{1}{4}

The solutions to the quadratic equation are:

a = \frac{5}{3}, a = - \frac{1}{4}

0 = - x^{2} - 4 x - 4

- 9 x^{2} - 6 x - 5 = 0

2 q^{2} + 10 q - 9 = 0

x^{2} - 20 x + 90 = 0

2 y^{2} - 3 y - 9 = 0

What are the solutions to the equation 12a^2-22a-5=-5a ?
The solutions to the equation 12a^2-22a-5=-5a are a= 5/3 ,a=-1/4
Find the zeros of 12a^2-22a-5=-5a
The zeros of 12a^2-22a-5=-5a are a= 5/3 ,a=-1/4