What are the solutions to the equation -3x+2x^2=2 ?

The solutions to the equation -3x+2x^2=2 are x=2,x=-1/2

Find the zeros of -3x+2x^2=2

The zeros of -3x+2x^2=2 are x=2,x=-1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 3 x + 2 x^{2} = 2

x = 2, x = - \frac{1}{2}

Decimal Notation

x = 2, x = - 0.5

Solution steps

- 3 x + 2 x^{2} = 2

Move

2

to the left side

- 3 x + 2 x^{2} - 2 = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} - 3 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 2 ( - 2 )}{2 \cdot 2}

(- 3)^{2} - 4 \cdot 2 (- 2) = 5

x_{1, 2} = \frac{- ( - 3 ) \pm 5}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 5}{2 \cdot 2}, x_{2} = \frac{- ( - 3 ) - 5}{2 \cdot 2}

x = \frac{- ( - 3 ) + 5}{2 \cdot 2} : 2

x = \frac{- ( - 3 ) - 5}{2 \cdot 2} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = 2, x = - \frac{1}{2}

2 x^{2} - 28 x = - 76

(2 x + 1)^{2} = 31

3 (x - 1) = 4 x^{2}

(m - 1) x^{2} - 3 m x + m + 1 = 0

42 x^{2} + 11 x - 20 = 0

What are the solutions to the equation -3x+2x^2=2 ?
The solutions to the equation -3x+2x^2=2 are x=2,x=-1/2
Find the zeros of -3x+2x^2=2
The zeros of -3x+2x^2=2 are x=2,x=-1/2