What are the solutions to the equation 2x^2-28x=-76 ?

The solutions to the equation 2x^2-28x=-76 are x=7+sqrt(11),x=7-sqrt(11)

Find the zeros of 2x^2-28x=-76

The zeros of 2x^2-28x=-76 are x=7+sqrt(11),x=7-sqrt(11)

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2 x^{2} - 28 x = - 76

x = 7 + 11, x = 7 - 11

Decimal Notation

x = 10.31662 \dots, x = 3.68337 \dots

Solution steps

2 x^{2} - 28 x = - 76

Move

76

to the left side

2 x^{2} - 28 x + 76 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 28 ) \pm ( - 28 ) ^{2} - 4 \cdot 2 \cdot 76}{2 \cdot 2}

(- 28)^{2} - 4 \cdot 2 \cdot 76 = 411

x_{1, 2} = \frac{- ( - 28 ) \pm 4 11}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 28 ) + 4 11}{2 \cdot 2}, x_{2} = \frac{- ( - 28 ) - 4 11}{2 \cdot 2}

x = \frac{- ( - 28 ) + 4 11}{2 \cdot 2} : 7 + 11

x = \frac{- ( - 28 ) - 4 11}{2 \cdot 2} : 7 - 11

The solutions to the quadratic equation are:

x = 7 + 11, x = 7 - 11

(2 x + 1)^{2} = 31

3 (x - 1) = 4 x^{2}

(m - 1) x^{2} - 3 m x + m + 1 = 0

42 x^{2} + 11 x - 20 = 0

x, (x - a)^{2} + y^{2} = a^{2}

What are the solutions to the equation 2x^2-28x=-76 ?
The solutions to the equation 2x^2-28x=-76 are x=7+sqrt(11),x=7-sqrt(11)
Find the zeros of 2x^2-28x=-76
The zeros of 2x^2-28x=-76 are x=7+sqrt(11),x=7-sqrt(11)