What are the solutions to the equation 196x^2+49x+2=0 ?

The solutions to the equation 196x^2+49x+2=0 are x=(-7+sqrt(17))/(56),x=-(7+sqrt(17))/(56)

Find the zeros of 196x^2+49x+2=0

The zeros of 196x^2+49x+2=0 are x=(-7+sqrt(17))/(56),x=-(7+sqrt(17))/(56)

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196 x^{2} + 49 x + 2 = 0

x = \frac{- 7 + 17}{56}, x = - \frac{7 + 17}{56}

Decimal Notation

x = - 0.05137 \dots, x = - 0.19862 \dots

Solution steps

196 x^{2} + 49 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 49 \pm 4 9 ^{2} - 4 \cdot 196 \cdot 2}{2 \cdot 196}

4 9^{2} - 4 \cdot 196 \cdot 2 = 717

x_{1, 2} = \frac{- 49 \pm 7 17}{2 \cdot 196}

Separate the solutions

x_{1} = \frac{- 49 + 7 17}{2 \cdot 196}, x_{2} = \frac{- 49 - 7 17}{2 \cdot 196}

x = \frac{- 49 + 7 17}{2 \cdot 196} : \frac{- 7 + 17}{56}

x = \frac{- 49 - 7 17}{2 \cdot 196} : - \frac{7 + 17}{56}

The solutions to the quadratic equation are:

x = \frac{- 7 + 17}{56}, x = - \frac{7 + 17}{56}

x, x^{2} + k x + 36 = 0

(x + 1)^{2} = - 48

\frac{7}{4} x^{2} + 4 x + 5 = 0

3 (3 x - 2) = (x - 4) (4 - x)

3 (3 x - 1)^{2} + 34 = 46

What are the solutions to the equation 196x^2+49x+2=0 ?
The solutions to the equation 196x^2+49x+2=0 are x=(-7+sqrt(17))/(56),x=-(7+sqrt(17))/(56)
Find the zeros of 196x^2+49x+2=0
The zeros of 196x^2+49x+2=0 are x=(-7+sqrt(17))/(56),x=-(7+sqrt(17))/(56)