What are the solutions to the equation (x^2+x)/2 =0 ?

The solutions to the equation (x^2+x)/2 =0 are x=0,x=-1

Find the zeros of (x^2+x)/2 =0

The zeros of (x^2+x)/2 =0 are x=0,x=-1

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\frac{x ^{2} + x}{2} = 0

x = 0, x = - 1

Solution steps

\frac{x ^{2} + x}{2} = 0

Multiply both sides by

2

x^{2} + x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot 0 = 1

x_{1, 2} = \frac{- 1 \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 1}{2 \cdot 1}, x_{2} = \frac{- 1 - 1}{2 \cdot 1}

x = \frac{- 1 + 1}{2 \cdot 1} : 0

x = \frac{- 1 - 1}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 0, x = - 1

u^{2} = - 64

\frac{3}{8} x^{2} + 3 x + \frac{9}{2} = 0

3 x^{2} - 40 = 7 x

y^{2} - 5 y = - 6

t, h = \frac{1}{2} g t^{2} + v t

What are the solutions to the equation (x^2+x)/2 =0 ?
The solutions to the equation (x^2+x)/2 =0 are x=0,x=-1
Find the zeros of (x^2+x)/2 =0
The zeros of (x^2+x)/2 =0 are x=0,x=-1