What are the solutions to the equation 3x^2-40=7x ?

The solutions to the equation 3x^2-40=7x are x=5,x=-8/3

Find the zeros of 3x^2-40=7x

The zeros of 3x^2-40=7x are x=5,x=-8/3

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3 x^{2} - 40 = 7 x

x = 5, x = - \frac{8}{3}

Decimal Notation

x = 5, x = - 2.66666 \dots

Solution steps

3 x^{2} - 40 = 7 x

Move

7 x

to the left side

3 x^{2} - 40 - 7 x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} - 7 x - 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 3 ( - 40 )}{2 \cdot 3}

(- 7)^{2} - 4 \cdot 3 (- 40) = 23

x_{1, 2} = \frac{- ( - 7 ) \pm 23}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 23}{2 \cdot 3}, x_{2} = \frac{- ( - 7 ) - 23}{2 \cdot 3}

x = \frac{- ( - 7 ) + 23}{2 \cdot 3} : 5

x = \frac{- ( - 7 ) - 23}{2 \cdot 3} : - \frac{8}{3}

The solutions to the quadratic equation are:

x = 5, x = - \frac{8}{3}

y^{2} - 5 y = - 6

t, h = \frac{1}{2} g t^{2} + v t

(2 x + 10) x = 100

7 (x - 4)^{2} - 2 = 54

3 b^{2} - 10 b - 8 = 0

What are the solutions to the equation 3x^2-40=7x ?
The solutions to the equation 3x^2-40=7x are x=5,x=-8/3
Find the zeros of 3x^2-40=7x
The zeros of 3x^2-40=7x are x=5,x=-8/3