What are the solutions to the equation 12m^2-4m-17=0 ?

The solutions to the equation 12m^2-4m-17=0 are m=(1+2sqrt(13))/6 ,m=(1-2sqrt(13))/6

Find the zeros of 12m^2-4m-17=0

The zeros of 12m^2-4m-17=0 are m=(1+2sqrt(13))/6 ,m=(1-2sqrt(13))/6

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12 m^{2} - 4 m - 17 = 0

m = \frac{1 + 2 13}{6}, m = \frac{1 - 2 13}{6}

Decimal Notation

m = 1.36851 \dots, m = - 1.03518 \dots

Solution steps

12 m^{2} - 4 m - 17 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 12 ( - 17 )}{2 \cdot 12}

(- 4)^{2} - 4 \cdot 12 (- 17) = 813

m_{1, 2} = \frac{- ( - 4 ) \pm 8 13}{2 \cdot 12}

Separate the solutions

m_{1} = \frac{- ( - 4 ) + 8 13}{2 \cdot 12}, m_{2} = \frac{- ( - 4 ) - 8 13}{2 \cdot 12}

m = \frac{- ( - 4 ) + 8 13}{2 \cdot 12} : \frac{1 + 2 13}{6}

m = \frac{- ( - 4 ) - 8 13}{2 \cdot 12} : \frac{1 - 2 13}{6}

The solutions to the quadratic equation are:

m = \frac{1 + 2 13}{6}, m = \frac{1 - 2 13}{6}

b^{2} - 4 b - 3 = 0

x^{2} - 3 x + 2 = 0

x^{2} - 6 x + 34

x^{2} - 3 x + 1 = 0

P, \frac{P V}{T} = \frac{P ^{2} V ^{2}}{T ^{2}}

What are the solutions to the equation 12m^2-4m-17=0 ?
The solutions to the equation 12m^2-4m-17=0 are m=(1+2sqrt(13))/6 ,m=(1-2sqrt(13))/6
Find the zeros of 12m^2-4m-17=0
The zeros of 12m^2-4m-17=0 are m=(1+2sqrt(13))/6 ,m=(1-2sqrt(13))/6