What are the solutions to the equation b^2-4b-3=0 ?

The solutions to the equation b^2-4b-3=0 are b=2+sqrt(7),b=2-sqrt(7)

Find the zeros of b^2-4b-3=0

The zeros of b^2-4b-3=0 are b=2+sqrt(7),b=2-sqrt(7)

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b^{2} - 4 b - 3 = 0

b = 2 + 7, b = 2 - 7

Decimal Notation

b = 4.64575 \dots, b = - 0.64575 \dots

Solution steps

b^{2} - 4 b - 3 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 3) = 27

b_{1, 2} = \frac{- ( - 4 ) \pm 2 7}{2 \cdot 1}

Separate the solutions

b_{1} = \frac{- ( - 4 ) + 2 7}{2 \cdot 1}, b_{2} = \frac{- ( - 4 ) - 2 7}{2 \cdot 1}

b = \frac{- ( - 4 ) + 2 7}{2 \cdot 1} : 2 + 7

b = \frac{- ( - 4 ) - 2 7}{2 \cdot 1} : 2 - 7

The solutions to the quadratic equation are:

b = 2 + 7, b = 2 - 7

x^{2} - 3 x + 2 = 0

x^{2} - 6 x + 34

x^{2} - 3 x + 1 = 0

P, \frac{P V}{T} = \frac{P ^{2} V ^{2}}{T ^{2}}

- 2 \cdot x^{2} + 11 \cdot x + c = 0

What are the solutions to the equation b^2-4b-3=0 ?
The solutions to the equation b^2-4b-3=0 are b=2+sqrt(7),b=2-sqrt(7)
Find the zeros of b^2-4b-3=0
The zeros of b^2-4b-3=0 are b=2+sqrt(7),b=2-sqrt(7)