What are the solutions to the equation roots x^2-3x+2=0 ?

The solutions to the equation roots x^2-3x+2=0 are x=2,x=1

Find the zeros of roots x^2-3x+2=0

The zeros of roots x^2-3x+2=0 are x=2,x=1

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roots

x^{2} - 3 x + 2 = 0

x = 2, x = 1

Solution steps

x^{2} - 3 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot 2 = 1

x_{1, 2} = \frac{- ( - 3 ) \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 1}{2 \cdot 1}

x = \frac{- ( - 3 ) + 1}{2 \cdot 1} : 2

x = \frac{- ( - 3 ) - 1}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 2, x = 1

x^{2} - 6 x + 34

x^{2} - 3 x + 1 = 0

P, \frac{P V}{T} = \frac{P ^{2} V ^{2}}{T ^{2}}

- 2 \cdot x^{2} + 11 \cdot x + c = 0

(2 x + 10) (x - 4) = 0

What are the solutions to the equation roots x^2-3x+2=0 ?
The solutions to the equation roots x^2-3x+2=0 are x=2,x=1
Find the zeros of roots x^2-3x+2=0
The zeros of roots x^2-3x+2=0 are x=2,x=1