What are the solutions to the equation X^2+25=-10X ?

The solutions to the equation X^2+25=-10X are X=-5

Find the zeros of X^2+25=-10X

The zeros of X^2+25=-10X are X=-5

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X^{2} + 25 = - 10 X

X = - 5

Solution steps

X^{2} + 25 = - 10 X

Move

10 X

to the left side

X^{2} + 25 + 10 X = 0

Write in the standard form

a x^{2} + b x + c = 0

X^{2} + 10 X + 25 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 25 = 0

X_{1, 2} = \frac{- 10 \pm 0}{2 \cdot 1}

X = \frac{- 10}{2 \cdot 1}

\frac{- 10}{2 \cdot 1} = - 5

X = - 5

The solution to the quadratic equation is:

X = - 5

4 x^{2} - 4 x + 1 = 0

(12 x + 18) (1.6 - 0.2 x) = 0

7 m + m^{2} + 10 = 0

3 x^{2} + \frac{9}{2} x - 4 = 5 x + \frac{3}{4}

y, x + x y + 2 y^{2} = 6

What are the solutions to the equation X^2+25=-10X ?
The solutions to the equation X^2+25=-10X are X=-5
Find the zeros of X^2+25=-10X
The zeros of X^2+25=-10X are X=-5