What are the solutions to the equation 32x^2-18x+17=0 ?

The solutions to the equation 32x^2-18x+17=0 are x= 9/32+i(sqrt(463))/(32),x= 9/32-i(sqrt(463))/(32)

Find the zeros of 32x^2-18x+17=0

The zeros of 32x^2-18x+17=0 are x= 9/32+i(sqrt(463))/(32),x= 9/32-i(sqrt(463))/(32)

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32 x^{2} - 18 x + 17 = 0

x = \frac{9}{32} + i \frac{463}{32}, x = \frac{9}{32} - i \frac{463}{32}

Solution steps

32 x^{2} - 18 x + 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 32 \cdot 17}{2 \cdot 32}

Simplify

(- 18)^{2} - 4 \cdot 32 \cdot 17 : 2463 i

x_{1, 2} = \frac{- ( - 18 ) \pm 2 463 i}{2 \cdot 32}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 2 463 i}{2 \cdot 32}, x_{2} = \frac{- ( - 18 ) - 2 463 i}{2 \cdot 32}

x = \frac{- ( - 18 ) + 2 463 i}{2 \cdot 32} : \frac{9}{32} + i \frac{463}{32}

x = \frac{- ( - 18 ) - 2 463 i}{2 \cdot 32} : \frac{9}{32} - i \frac{463}{32}

The solutions to the quadratic equation are:

x = \frac{9}{32} + i \frac{463}{32}, x = \frac{9}{32} - i \frac{463}{32}

5 a^{2} - 17 a + 1

5 x^{2} - 7 x - 1 = 2 x

x^{2} + 26 x = 16

d^{2} - 6 d - 475 = 0

2 x^{2} - 6 x + 7 = 10.5

What are the solutions to the equation 32x^2-18x+17=0 ?
The solutions to the equation 32x^2-18x+17=0 are x= 9/32+i(sqrt(463))/(32),x= 9/32-i(sqrt(463))/(32)
Find the zeros of 32x^2-18x+17=0
The zeros of 32x^2-18x+17=0 are x= 9/32+i(sqrt(463))/(32),x= 9/32-i(sqrt(463))/(32)