What are the solutions to the equation d^2-6d-475=0 ?

The solutions to the equation d^2-6d-475=0 are d=25,d=-19

Find the zeros of d^2-6d-475=0

The zeros of d^2-6d-475=0 are d=25,d=-19

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

d^{2} - 6 d - 475 = 0

d = 25, d = - 19

Solution steps

d^{2} - 6 d - 475 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 475 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 475) = 44

d_{1, 2} = \frac{- ( - 6 ) \pm 44}{2 \cdot 1}

Separate the solutions

d_{1} = \frac{- ( - 6 ) + 44}{2 \cdot 1}, d_{2} = \frac{- ( - 6 ) - 44}{2 \cdot 1}

d = \frac{- ( - 6 ) + 44}{2 \cdot 1} : 25

d = \frac{- ( - 6 ) - 44}{2 \cdot 1} : - 19

The solutions to the quadratic equation are:

d = 25, d = - 19

2 x^{2} - 6 x + 7 = 10.5

9 x^{2} + 5 x = 12 + 6 x + 3 x^{2}

2 x^{2} - x - 1

16 n^{2} = 25

y, (x + 2)^{2} + (y - 4)^{2} = - 12

What are the solutions to the equation d^2-6d-475=0 ?
The solutions to the equation d^2-6d-475=0 are d=25,d=-19
Find the zeros of d^2-6d-475=0
The zeros of d^2-6d-475=0 are d=25,d=-19