What are the solutions to the equation x^2-14x+92=2 ?

The solutions to the equation x^2-14x+92=2 are x=7+sqrt(41)i,x=7-sqrt(41)i

Find the zeros of x^2-14x+92=2

The zeros of x^2-14x+92=2 are x=7+sqrt(41)i,x=7-sqrt(41)i

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x^{2} - 14 x + 92 = 2

x = 7 + 41 i, x = 7 - 41 i

Solution steps

x^{2} - 14 x + 92 = 2

Move

2

to the left side

x^{2} - 14 x + 90 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 90}{2 \cdot 1}

Simplify

(- 14)^{2} - 4 \cdot 1 \cdot 90 : 241 i

x_{1, 2} = \frac{- ( - 14 ) \pm 2 41 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 2 41 i}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 2 41 i}{2 \cdot 1}

x = \frac{- ( - 14 ) + 2 41 i}{2 \cdot 1} : 7 + 41 i

x = \frac{- ( - 14 ) - 2 41 i}{2 \cdot 1} : 7 - 41 i

The solutions to the quadratic equation are:

x = 7 + 41 i, x = 7 - 41 i

1 0^{2} + 6^{2} = c^{2}

x^{2} - 8 x + 31 = 0

x^{2} - x + 5 = 5

9 x^{2} + 6 x - 2 = 0

x (x + 21) = 100

What are the solutions to the equation x^2-14x+92=2 ?
The solutions to the equation x^2-14x+92=2 are x=7+sqrt(41)i,x=7-sqrt(41)i
Find the zeros of x^2-14x+92=2
The zeros of x^2-14x+92=2 are x=7+sqrt(41)i,x=7-sqrt(41)i