What are the solutions to the equation 9r^2+6r+4=0 ?

The solutions to the equation 9r^2+6r+4=0 are r=-1/3+i(sqrt(3))/3 ,r=-1/3-i(sqrt(3))/3

Find the zeros of 9r^2+6r+4=0

The zeros of 9r^2+6r+4=0 are r=-1/3+i(sqrt(3))/3 ,r=-1/3-i(sqrt(3))/3

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9 r^{2} + 6 r + 4 = 0

r = - \frac{1}{3} + i \frac{3}{3}, r = - \frac{1}{3} - i \frac{3}{3}

Solution steps

9 r^{2} + 6 r + 4 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 9 \cdot 4}{2 \cdot 9}

Simplify

6^{2} - 4 \cdot 9 \cdot 4 : 63 i

r_{1, 2} = \frac{- 6 \pm 6 3 i}{2 \cdot 9}

Separate the solutions

r_{1} = \frac{- 6 + 6 3 i}{2 \cdot 9}, r_{2} = \frac{- 6 - 6 3 i}{2 \cdot 9}

r = \frac{- 6 + 6 3 i}{2 \cdot 9} : - \frac{1}{3} + i \frac{3}{3}

r = \frac{- 6 - 6 3 i}{2 \cdot 9} : - \frac{1}{3} - i \frac{3}{3}

The solutions to the quadratic equation are:

r = - \frac{1}{3} + i \frac{3}{3}, r = - \frac{1}{3} - i \frac{3}{3}

16 (4 x - 5)^{2} = 9

(\frac{2}{5})^{2} + x^{2} = 1

x, x^{2} - 6 x + 8 = 0

12 x (x - 2) = 0

2 (1 - x^{2}) = 0

What are the solutions to the equation 9r^2+6r+4=0 ?
The solutions to the equation 9r^2+6r+4=0 are r=-1/3+i(sqrt(3))/3 ,r=-1/3-i(sqrt(3))/3
Find the zeros of 9r^2+6r+4=0
The zeros of 9r^2+6r+4=0 are r=-1/3+i(sqrt(3))/3 ,r=-1/3-i(sqrt(3))/3