What are the solutions to the equation 16(4x-5)^2=9 ?

The solutions to the equation 16(4x-5)^2=9 are x= 23/16 ,x= 17/16

Find the zeros of 16(4x-5)^2=9

The zeros of 16(4x-5)^2=9 are x= 23/16 ,x= 17/16

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16 (4 x - 5)^{2} = 9

x = \frac{23}{16}, x = \frac{17}{16}

Decimal Notation

x = 1.4375, x = 1.0625

Solution steps

16 (4 x - 5)^{2} = 9

Divide both sides by

16

(4 x - 5)^{2} = \frac{9}{16}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 x - 5 = \frac{9}{16} : x = \frac{23}{16}

Solve

4 x - 5 = - \frac{9}{16} : x = \frac{17}{16}

The solutions to the quadratic equation are:

x = \frac{23}{16}, x = \frac{17}{16}

(\frac{2}{5})^{2} + x^{2} = 1

x, x^{2} - 6 x + 8 = 0

12 x (x - 2) = 0

2 (1 - x^{2}) = 0

(2 x + 2) (x + 1) = 0

What are the solutions to the equation 16(4x-5)^2=9 ?
The solutions to the equation 16(4x-5)^2=9 are x= 23/16 ,x= 17/16
Find the zeros of 16(4x-5)^2=9
The zeros of 16(4x-5)^2=9 are x= 23/16 ,x= 17/16