What are the solutions to the equation roots x^2+6x+34 ?

The solutions to the equation roots x^2+6x+34 are x=-3+5i,x=-3-5i

Find the zeros of roots x^2+6x+34

The zeros of roots x^2+6x+34 are x=-3+5i,x=-3-5i

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roots

x^{2} + 6 x + 34

x = - 3 + 5 i, x = - 3 - 5 i

Solution steps

x^{2} + 6 x + 34

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + 6 x + 34 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 34}{2 \cdot 1}

Simplify

6^{2} - 4 \cdot 1 \cdot 34 : 10 i

x_{1, 2} = \frac{- 6 \pm 10 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 10 i}{2 \cdot 1}, x_{2} = \frac{- 6 - 10 i}{2 \cdot 1}

x = \frac{- 6 + 10 i}{2 \cdot 1} : - 3 + 5 i

x = \frac{- 6 - 10 i}{2 \cdot 1} : - 3 - 5 i

The solutions to the quadratic equation are:

x = - 3 + 5 i, x = - 3 - 5 i

x^{2} - 15 x + 44 = 0

1.33 x^{2} - 39.53 x + 793.16 = 0

m^{2} - 6 m + 3 = 0

9 x^{2} + 60 x + 95 = - 5

- 6 x^{2} + 9 x - 7 = 0

What are the solutions to the equation roots x^2+6x+34 ?
The solutions to the equation roots x^2+6x+34 are x=-3+5i,x=-3-5i
Find the zeros of roots x^2+6x+34
The zeros of roots x^2+6x+34 are x=-3+5i,x=-3-5i