What are the solutions to the equation 2n^2-3=-12 ?

The solutions to the equation 2n^2-3=-12 are n= 3/(sqrt(2))i,n=-3/(sqrt(2))i

Find the zeros of 2n^2-3=-12

The zeros of 2n^2-3=-12 are n= 3/(sqrt(2))i,n=-3/(sqrt(2))i

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2 n^{2} - 3 = - 12

n = \frac{3}{2} i, n = - \frac{3}{2} i

Solution steps

2 n^{2} - 3 = - 12

Move

3

to the right side

2 n^{2} = - 9

Divide both sides by

2

n^{2} = - \frac{9}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

n = - \frac{9}{2}, n = - - \frac{9}{2}

- \frac{9}{2} = \frac{3}{2} i

- - \frac{9}{2} = - \frac{3}{2} i

n = \frac{3}{2} i, n = - \frac{3}{2} i

3 x^{2} + 32 x + 76 = 7

x^{2} + x = - 12

16 y^{2} - 2 y - 3 = 0

49 x^{2} = 1

16 x^{2} + 2 x - 3 = 0

What are the solutions to the equation 2n^2-3=-12 ?
The solutions to the equation 2n^2-3=-12 are n= 3/(sqrt(2))i,n=-3/(sqrt(2))i
Find the zeros of 2n^2-3=-12
The zeros of 2n^2-3=-12 are n= 3/(sqrt(2))i,n=-3/(sqrt(2))i