What is the answer to solvefor y,x^2+y^2-5=2xy+y^2-5 ?

The answer to solvefor y,x^2+y^2-5=2xy+y^2-5 is y= x/2 ;\quad x\ne 0

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solvefor y,x^2+y^2-5=2xy+y^2-5

solve for

y, x^{2} + y^{2} - 5 = 2 x y + y^{2} - 5

y = \frac{x}{2}; x \neq = 0

Solution steps

x^{2} + y^{2} - 5 = 2 x y + y^{2} - 5

Subtract

y^{2} - 5

from both sides

x^{2} + y^{2} - 5 - (y^{2} - 5) = 2 x y + y^{2} - 5 - (y^{2} - 5)

Simplify

x^{2} = 2 x y

Switch sides

2 x y = x^{2}

Divide both sides by

2 x; x \neq = 0

y = \frac{x}{2}; x \neq = 0

0 = 6 x^{2} - 7 x + 2

x^{2} + 6 = 8 x

x, x^{2} - 15 x = 0

9 x^{2} + 18 x - 27 = 0

- 2 x^{2} - 2 x = 0

What is the answer to solvefor y,x^2+y^2-5=2xy+y^2-5 ?
The answer to solvefor y,x^2+y^2-5=2xy+y^2-5 is y= x/2 ;\quad x\ne 0