What are the solutions to the equation 144=(n+1)^2 ?

The solutions to the equation 144=(n+1)^2 are n=11,n=-13

Find the zeros of 144=(n+1)^2

The zeros of 144=(n+1)^2 are n=11,n=-13

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

144 = (n + 1)^{2}

n = 11, n = - 13

Solution steps

144 = (n + 1)^{2}

Switch sides

(n + 1)^{2} = 144

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

n + 1 = 144 : n = 11

Solve

n + 1 = - 144 : n = - 13

The solutions to the quadratic equation are:

n = 11, n = - 13

2 W^{2} + 7 W - 99 = 0

4 x^{2} - 90 = 2 x

y, 4 x^{2} - 9 y^{2} - 16 x - 18 y + 7 = 0

x^{2} - 5 x - 10

a^{2} = 196

What are the solutions to the equation 144=(n+1)^2 ?
The solutions to the equation 144=(n+1)^2 are n=11,n=-13
Find the zeros of 144=(n+1)^2
The zeros of 144=(n+1)^2 are n=11,n=-13