What are the solutions to the equation -8x^2+40=0 ?

The solutions to the equation -8x^2+40=0 are x=sqrt(5),x=-sqrt(5)

Find the zeros of -8x^2+40=0

The zeros of -8x^2+40=0 are x=sqrt(5),x=-sqrt(5)

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- 8 x^{2} + 40 = 0

x = 5, x = - 5

Decimal Notation

x = 2.23606 \dots, x = - 2.23606 \dots

Solution steps

- 8 x^{2} + 40 = 0

Move

40

to the right side

- 8 x^{2} = - 40

Divide both sides by

- 8

x^{2} = 5

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 5, x = - 5

x^{2} + 36 x + c

x^{2} + 49

4 x^{2} + 6 x = 12

x^{2} + 81

a^{2} = 5 a + 104

What are the solutions to the equation -8x^2+40=0 ?
The solutions to the equation -8x^2+40=0 are x=sqrt(5),x=-sqrt(5)
Find the zeros of -8x^2+40=0
The zeros of -8x^2+40=0 are x=sqrt(5),x=-sqrt(5)