What are the solutions to the equation -x^2+6x+3=x+3 ?

The solutions to the equation -x^2+6x+3=x+3 are x=0,x=5

Find the zeros of -x^2+6x+3=x+3

The zeros of -x^2+6x+3=x+3 are x=0,x=5

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- x^{2} + 6 x + 3 = x + 3

x = 0, x = 5

Solution steps

- x^{2} + 6 x + 3 = x + 3

Move

3

to the left side

- x^{2} + 6 x = x

Move

x

to the left side

- x^{2} + 5 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

5^{2} - 4 (- 1) \cdot 0 = 5

x_{1, 2} = \frac{- 5 \pm 5}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 5 + 5}{2 ( - 1 )}, x_{2} = \frac{- 5 - 5}{2 ( - 1 )}

x = \frac{- 5 + 5}{2 ( - 1 )} : 0

x = \frac{- 5 - 5}{2 ( - 1 )} : 5

The solutions to the quadratic equation are:

x = 0, x = 5

4 x^{2} + x + 12 = 0

5 x^{2} - 37 x - 24 = 0

8 x^{2} + 2 x - 1 = 0

5 (5 x - 6)^{2} - 27 = 18

3 x^{2} + 5 x + 1 = 0

What are the solutions to the equation -x^2+6x+3=x+3 ?
The solutions to the equation -x^2+6x+3=x+3 are x=0,x=5
Find the zeros of -x^2+6x+3=x+3
The zeros of -x^2+6x+3=x+3 are x=0,x=5