What are the solutions to the equation factor 8x^2+2x-1=0 ?

The solutions to the equation factor 8x^2+2x-1=0 are x= 1/4 ,x=-1/2

Find the zeros of factor 8x^2+2x-1=0

The zeros of factor 8x^2+2x-1=0 are x= 1/4 ,x=-1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

8 x^{2} + 2 x - 1 = 0

x = \frac{1}{4}, x = - \frac{1}{2}

Decimal Notation

x = 0.25, x = - 0.5

Solution steps

8 x^{2} + 2 x - 1 = 0

Factor

8 x^{2} + 2 x - 1 : (4 x - 1) (2 x + 1)

(4 x - 1) (2 x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

4 x - 1 = 0 or 2 x + 1 = 0

Solve

4 x - 1 = 0 : x = \frac{1}{4}

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{1}{4}, x = - \frac{1}{2}

5 (5 x - 6)^{2} - 27 = 18

3 x^{2} + 5 x + 1 = 0

a^{2} = - 5 a + 6

(60 - 3 x) \times (32 - x) = 480

- x^{2} = 12

What are the solutions to the equation factor 8x^2+2x-1=0 ?
The solutions to the equation factor 8x^2+2x-1=0 are x= 1/4 ,x=-1/2
Find the zeros of factor 8x^2+2x-1=0
The zeros of factor 8x^2+2x-1=0 are x= 1/4 ,x=-1/2