What are the solutions to the equation a^2+10a+2=0 ?

The solutions to the equation a^2+10a+2=0 are a=-5+sqrt(23),a=-5-sqrt(23)

Find the zeros of a^2+10a+2=0

The zeros of a^2+10a+2=0 are a=-5+sqrt(23),a=-5-sqrt(23)

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a^{2} + 10 a + 2 = 0

a = - 5 + 23, a = - 5 - 23

Decimal Notation

a = - 0.20416 \dots, a = - 9.79583 \dots

Solution steps

a^{2} + 10 a + 2 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 2 = 223

a_{1, 2} = \frac{- 10 \pm 2 23}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- 10 + 2 23}{2 \cdot 1}, a_{2} = \frac{- 10 - 2 23}{2 \cdot 1}

a = \frac{- 10 + 2 23}{2 \cdot 1} : - 5 + 23

a = \frac{- 10 - 2 23}{2 \cdot 1} : - 5 - 23

The solutions to the quadratic equation are:

a = - 5 + 23, a = - 5 - 23

x^{2} - 2 (1) - 4 x = 0

- 4 x^{2} - 2 x + 6 = 0

0 = - 0.08 x^{2} + 40 x - 1800

25 (x^{2} - 1) + 12 = - 12

- x - 2 = x^{2} + 4 x + 4

What are the solutions to the equation a^2+10a+2=0 ?
The solutions to the equation a^2+10a+2=0 are a=-5+sqrt(23),a=-5-sqrt(23)
Find the zeros of a^2+10a+2=0
The zeros of a^2+10a+2=0 are a=-5+sqrt(23),a=-5-sqrt(23)