What are the solutions to the equation completesquare x^2+5x=23-x ?

The solutions to the equation completesquare x^2+5x=23-x are x=4sqrt(2)-3,x=-4sqrt(2)-3

Find the zeros of completesquare x^2+5x=23-x

The zeros of completesquare x^2+5x=23-x are x=4sqrt(2)-3,x=-4sqrt(2)-3

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x^{2} + 5 x = 23 - x

x = 42 - 3, x = - 42 - 3

Decimal Notation

x = 2.65685 \dots, x = - 8.65685 \dots

Solution steps

x^{2} + 5 x = 23 - x

Move

x

to the left side

x^{2} + 6 x = 23

Rewrite in the form

(x + a)^{2} = b

(x + 3)^{2} = 32

For

the solutions are

f (x) = a, - a

Solve

x + 3 = 32 : x = 42 - 3

Solve

x + 3 = - 32 : x = - 42 - 3

The solutions to the quadratic equation are:

x = 42 - 3, x = - 42 - 3

- 3 x^{2} - 6 x - 4 = 0

y, x^{2} y + x y^{2} = 3 x

5 x^{2} + 13 x - 18 = 0

12 x^{2} + 24 x - 15 = 0

9 (3 x - 3)^{2} + 25 = 26

What are the solutions to the equation completesquare x^2+5x=23-x ?
The solutions to the equation completesquare x^2+5x=23-x are x=4sqrt(2)-3,x=-4sqrt(2)-3
Find the zeros of completesquare x^2+5x=23-x
The zeros of completesquare x^2+5x=23-x are x=4sqrt(2)-3,x=-4sqrt(2)-3