What are the solutions to the equation 2x^2-2x-16=0 ?

The solutions to the equation 2x^2-2x-16=0 are x=(1+sqrt(33))/2 ,x=(1-sqrt(33))/2

Find the zeros of 2x^2-2x-16=0

The zeros of 2x^2-2x-16=0 are x=(1+sqrt(33))/2 ,x=(1-sqrt(33))/2

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2 x^{2} - 2 x - 16 = 0

x = \frac{1 + 33}{2}, x = \frac{1 - 33}{2}

Decimal Notation

x = 3.37228 \dots, x = - 2.37228 \dots

Solution steps

2 x^{2} - 2 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 2 ( - 16 )}{2 \cdot 2}

(- 2)^{2} - 4 \cdot 2 (- 16) = 233

x_{1, 2} = \frac{- ( - 2 ) \pm 2 33}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 33}{2 \cdot 2}, x_{2} = \frac{- ( - 2 ) - 2 33}{2 \cdot 2}

x = \frac{- ( - 2 ) + 2 33}{2 \cdot 2} : \frac{1 + 33}{2}

x = \frac{- ( - 2 ) - 2 33}{2 \cdot 2} : \frac{1 - 33}{2}

The solutions to the quadratic equation are:

x = \frac{1 + 33}{2}, x = \frac{1 - 33}{2}

x^{2} - 4 x + 36 = 0

3 x^{2} - 4 x + 5 = 4

2 x^{2} + 5 x - 11 = 1

s^{2} + 14 s + 2

2 x^{2} - 11 x + 14

What are the solutions to the equation 2x^2-2x-16=0 ?
The solutions to the equation 2x^2-2x-16=0 are x=(1+sqrt(33))/2 ,x=(1-sqrt(33))/2
Find the zeros of 2x^2-2x-16=0
The zeros of 2x^2-2x-16=0 are x=(1+sqrt(33))/2 ,x=(1-sqrt(33))/2