What are the solutions to the equation -5x^2-99x-480=x ?

The solutions to the equation -5x^2-99x-480=x are x=-12,x=-8

Find the zeros of -5x^2-99x-480=x

The zeros of -5x^2-99x-480=x are x=-12,x=-8

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- 5 x^{2} - 99 x - 480 = x

x = - 12, x = - 8

Solution steps

- 5 x^{2} - 99 x - 480 = x

Move

x

to the left side

- 5 x^{2} - 100 x - 480 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 100 ) \pm ( - 100 ) ^{2} - 4 ( - 5 ) ( - 480 )}{2 ( - 5 )}

(- 100)^{2} - 4 (- 5) (- 480) = 20

x_{1, 2} = \frac{- ( - 100 ) \pm 20}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- ( - 100 ) + 20}{2 ( - 5 )}, x_{2} = \frac{- ( - 100 ) - 20}{2 ( - 5 )}

x = \frac{- ( - 100 ) + 20}{2 ( - 5 )} : - 12

x = \frac{- ( - 100 ) - 20}{2 ( - 5 )} : - 8

The solutions to the quadratic equation are:

x = - 12, x = - 8

30 x^{2} + 40 = 0

4 x^{2} + 4 x = 1

120 = (2 x - 1) (x)

x^{2} - 6 = - 4 x - 6

x, z = 8 - x^{2} - y^{2}

What are the solutions to the equation -5x^2-99x-480=x ?
The solutions to the equation -5x^2-99x-480=x are x=-12,x=-8
Find the zeros of -5x^2-99x-480=x
The zeros of -5x^2-99x-480=x are x=-12,x=-8