What are the solutions to the equation 4x^2+75=0 ?

The solutions to the equation 4x^2+75=0 are x=(5sqrt(3))/2 i,x=-(5sqrt(3))/2 i

Find the zeros of 4x^2+75=0

The zeros of 4x^2+75=0 are x=(5sqrt(3))/2 i,x=-(5sqrt(3))/2 i

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4 x^{2} + 75 = 0

x = \frac{5 3}{2} i, x = - \frac{5 3}{2} i

Solution steps

4 x^{2} + 75 = 0

Move

75

to the right side

4 x^{2} = - 75

Divide both sides by

4

x^{2} = - \frac{75}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{75}{4}, x = - - \frac{75}{4}

- \frac{75}{4} = \frac{5 3}{2} i

- - \frac{75}{4} = - \frac{5 3}{2} i

x = \frac{5 3}{2} i, x = - \frac{5 3}{2} i

9 x^{2} - 2880 = 0

2 n^{2} + 14 n + 8 = - 5

4 x^{2} = x^{2} + 3

y, a y^{2} = x (a^{2} - x^{2})

x^{2} - 15 x - 39 = - 30

What are the solutions to the equation 4x^2+75=0 ?
The solutions to the equation 4x^2+75=0 are x=(5sqrt(3))/2 i,x=-(5sqrt(3))/2 i
Find the zeros of 4x^2+75=0
The zeros of 4x^2+75=0 are x=(5sqrt(3))/2 i,x=-(5sqrt(3))/2 i