What are the solutions to the equation 2n^2+14n+8=-5 ?

The solutions to the equation 2n^2+14n+8=-5 are n=(-7+sqrt(23))/2 ,n=-(7+sqrt(23))/2

Find the zeros of 2n^2+14n+8=-5

The zeros of 2n^2+14n+8=-5 are n=(-7+sqrt(23))/2 ,n=-(7+sqrt(23))/2

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2 n^{2} + 14 n + 8 = - 5

n = \frac{- 7 + 23}{2}, n = - \frac{7 + 23}{2}

Decimal Notation

n = - 1.10208 \dots, n = - 5.89791 \dots

Solution steps

2 n^{2} + 14 n + 8 = - 5

Move

5

to the left side

2 n^{2} + 14 n + 13 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 2 \cdot 13}{2 \cdot 2}

1 4^{2} - 4 \cdot 2 \cdot 13 = 223

n_{1, 2} = \frac{- 14 \pm 2 23}{2 \cdot 2}

Separate the solutions

n_{1} = \frac{- 14 + 2 23}{2 \cdot 2}, n_{2} = \frac{- 14 - 2 23}{2 \cdot 2}

n = \frac{- 14 + 2 23}{2 \cdot 2} : \frac{- 7 + 23}{2}

n = \frac{- 14 - 2 23}{2 \cdot 2} : - \frac{7 + 23}{2}

The solutions to the quadratic equation are:

n = \frac{- 7 + 23}{2}, n = - \frac{7 + 23}{2}

4 x^{2} = x^{2} + 3

y, a y^{2} = x (a^{2} - x^{2})

x^{2} - 15 x - 39 = - 30

- 16 x^{2} = 200

x, x^{2} - 2 = 2 x - 2

What are the solutions to the equation 2n^2+14n+8=-5 ?
The solutions to the equation 2n^2+14n+8=-5 are n=(-7+sqrt(23))/2 ,n=-(7+sqrt(23))/2
Find the zeros of 2n^2+14n+8=-5
The zeros of 2n^2+14n+8=-5 are n=(-7+sqrt(23))/2 ,n=-(7+sqrt(23))/2