What are the solutions to the equation x^2+x^2=24^2 ?

The solutions to the equation x^2+x^2=24^2 are x=12sqrt(2),x=-12sqrt(2)

Find the zeros of x^2+x^2=24^2

The zeros of x^2+x^2=24^2 are x=12sqrt(2),x=-12sqrt(2)

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x^{2} + x^{2} = 2 4^{2}

x = 122, x = - 122

Decimal Notation

x = 16.97056 \dots, x = - 16.97056 \dots

Solution steps

x^{2} + x^{2} = 2 4^{2}

Add similar elements:

x^{2} + x^{2} = 2 x^{2}

2 x^{2} = 2 4^{2}

2 4^{2} = 576

2 x^{2} = 576

Divide both sides by

2

x^{2} = 288

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 288, x = - 288

288 = 122

- 288 = - 122

x = 122, x = - 122

0 = - 3 x^{2} - 6 x - 2

4 x^{2} - 3 x - 27 = 0

- 3 X^{2} + 18 X = - 30

4 (2 x - 2)^{2} = 16

x^{2} = 3 + 5 x - x^{2}

What are the solutions to the equation x^2+x^2=24^2 ?
The solutions to the equation x^2+x^2=24^2 are x=12sqrt(2),x=-12sqrt(2)
Find the zeros of x^2+x^2=24^2
The zeros of x^2+x^2=24^2 are x=12sqrt(2),x=-12sqrt(2)