What are the solutions to the equation roots x^2-8x+32=0 ?

The solutions to the equation roots x^2-8x+32=0 are x=4+4i,x=4-4i

Find the zeros of roots x^2-8x+32=0

The zeros of roots x^2-8x+32=0 are x=4+4i,x=4-4i

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roots

x^{2} - 8 x + 32 = 0

x = 4 + 4 i, x = 4 - 4 i

Solution steps

x^{2} - 8 x + 32 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 32}{2 \cdot 1}

Simplify

(- 8)^{2} - 4 \cdot 1 \cdot 32 : 8 i

x_{1, 2} = \frac{- ( - 8 ) \pm 8 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 8 i}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 8 i}{2 \cdot 1}

x = \frac{- ( - 8 ) + 8 i}{2 \cdot 1} : 4 + 4 i

x = \frac{- ( - 8 ) - 8 i}{2 \cdot 1} : 4 - 4 i

The solutions to the quadratic equation are:

x = 4 + 4 i, x = 4 - 4 i

(5 - 1) x^{2} - 2 x - (5 + 1) = 0

x, h^{- 1} (x) = \frac{1}{2} x^{2}

5 a^{2} - 7 a - 10 = 0

2 x^{2} + 24 x + 32 = 0

x^{2} + 15 x + 54 = 0

What are the solutions to the equation roots x^2-8x+32=0 ?
The solutions to the equation roots x^2-8x+32=0 are x=4+4i,x=4-4i
Find the zeros of roots x^2-8x+32=0
The zeros of roots x^2-8x+32=0 are x=4+4i,x=4-4i