What are the solutions to the equation completesquare n^2-7n-2=0 ?

The solutions to the equation completesquare n^2-7n-2=0 are n=(sqrt(57)+7)/2 ,n=(-sqrt(57)+7)/2

Find the zeros of completesquare n^2-7n-2=0

The zeros of completesquare n^2-7n-2=0 are n=(sqrt(57)+7)/2 ,n=(-sqrt(57)+7)/2

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n^{2} - 7 n - 2 = 0

n = \frac{57 + 7}{2}, n = \frac{- 57 + 7}{2}

Decimal Notation

n = 7.27491 \dots, n = - 0.27491 \dots

Solution steps

n^{2} - 7 n - 2 = 0

Move

2

to the right side

n^{2} - 7 n = 2

Rewrite in the form

(x + a)^{2} = b

(n - \frac{7}{2})^{2} = \frac{57}{4}

For

the solutions are

f (x) = a, - a

Solve

n - \frac{7}{2} = \frac{57}{4} : n = \frac{57 + 7}{2}

Solve

n - \frac{7}{2} = - \frac{57}{4} : n = \frac{- 57 + 7}{2}

The solutions to the quadratic equation are:

n = \frac{57 + 7}{2}, n = \frac{- 57 + 7}{2}

x^{2} + 10 x + 18

w^{2} + 16 w + 36 = 0

x^{2} - 5 x - 3 = 0

3 (5 x - 10)^{2} = 27

8 x^{2} + 2 x - 6 = 0

What are the solutions to the equation completesquare n^2-7n-2=0 ?
The solutions to the equation completesquare n^2-7n-2=0 are n=(sqrt(57)+7)/2 ,n=(-sqrt(57)+7)/2
Find the zeros of completesquare n^2-7n-2=0
The zeros of completesquare n^2-7n-2=0 are n=(sqrt(57)+7)/2 ,n=(-sqrt(57)+7)/2