What are the solutions to the equation x^2+4x+2.5=0 ?

The solutions to the equation x^2+4x+2.5=0 are x=(-4+sqrt(6))/2 ,x=-(4+sqrt(6))/2

Find the zeros of x^2+4x+2.5=0

The zeros of x^2+4x+2.5=0 are x=(-4+sqrt(6))/2 ,x=-(4+sqrt(6))/2

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x^{2} + 4 x + 2.5 = 0

x = \frac{- 4 + 6}{2}, x = - \frac{4 + 6}{2}

Decimal

x = - 0.77525 \dots, x = - 3.22474 \dots

Solution steps

x^{2} + 4 x + 2.5 = 0

Multiply both sides by

10

10 x^{2} + 40 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 \cdot 10 \cdot 25}{2 \cdot 10}

4 0^{2} - 4 \cdot 10 \cdot 25 = 106

x_{1, 2} = \frac{- 40 \pm 10 6}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 40 + 10 6}{2 \cdot 10}, x_{2} = \frac{- 40 - 10 6}{2 \cdot 10}

x = \frac{- 40 + 10 6}{2 \cdot 10} : \frac{- 4 + 6}{2}

x = \frac{- 40 - 10 6}{2 \cdot 10} : - \frac{4 + 6}{2}

The solutions to the quadratic equation are:

x = \frac{- 4 + 6}{2}, x = - \frac{4 + 6}{2}

x^{2} - 17 x = - 72

10 x^{2} + 4 x + 77 = 9

0 = (x - 11) (x - 1)

x^{2} - 12 x + 37

a^{2} + 12 a + 27 = 0

What are the solutions to the equation x^2+4x+2.5=0 ?
The solutions to the equation x^2+4x+2.5=0 are x=(-4+sqrt(6))/2 ,x=-(4+sqrt(6))/2
Find the zeros of x^2+4x+2.5=0
The zeros of x^2+4x+2.5=0 are x=(-4+sqrt(6))/2 ,x=-(4+sqrt(6))/2