What are the solutions to the equation roots x^2-12x+37 ?

The solutions to the equation roots x^2-12x+37 are x=6+i,x=6-i

Find the zeros of roots x^2-12x+37

The zeros of roots x^2-12x+37 are x=6+i,x=6-i

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roots

x^{2} - 12 x + 37

x = 6 + i, x = 6 - i

Solution steps

x^{2} - 12 x + 37

The roots are the intercepts with the x-axis

(y = 0)

x^{2} - 12 x + 37 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 37}{2 \cdot 1}

Simplify

(- 12)^{2} - 4 \cdot 1 \cdot 37 : 2 i

x_{1, 2} = \frac{- ( - 12 ) \pm 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 2 i}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 2 i}{2 \cdot 1}

x = \frac{- ( - 12 ) + 2 i}{2 \cdot 1} : 6 + i

x = \frac{- ( - 12 ) - 2 i}{2 \cdot 1} : 6 - i

The solutions to the quadratic equation are:

x = 6 + i, x = 6 - i

a^{2} + 12 a + 27 = 0

3 x^{2} - 7 = 7 x - 1

x^{2} + 16 x + 51 = 0

x^{2} + 9 = - 40

y, x^{2} y^{2} - 2 x y^{2} + y^{2} - x = 0

What are the solutions to the equation roots x^2-12x+37 ?
The solutions to the equation roots x^2-12x+37 are x=6+i,x=6-i
Find the zeros of roots x^2-12x+37
The zeros of roots x^2-12x+37 are x=6+i,x=6-i