What are the solutions to the equation -91.5x^2-18x+73.5=0 ?

The solutions to the equation -91.5x^2-18x+73.5=0 are x=-1,x= 49/61

Find the zeros of -91.5x^2-18x+73.5=0

The zeros of -91.5x^2-18x+73.5=0 are x=-1,x= 49/61

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- 91.5 x^{2} - 18 x + 73.5 = 0

x = - 1, x = \frac{49}{61}

Decimal Notation

x = - 1, x = 0.80327 \dots

Solution steps

- 91.5 x^{2} - 18 x + 73.5 = 0

Multiply both sides by

10

- 915 x^{2} - 180 x + 735 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 180 ) \pm ( - 180 ) ^{2} - 4 ( - 915 ) \cdot 735}{2 ( - 915 )}

(- 180)^{2} - 4 (- 915) \cdot 735 = 1650

x_{1, 2} = \frac{- ( - 180 ) \pm 1650}{2 ( - 915 )}

Separate the solutions

x_{1} = \frac{- ( - 180 ) + 1650}{2 ( - 915 )}, x_{2} = \frac{- ( - 180 ) - 1650}{2 ( - 915 )}

x = \frac{- ( - 180 ) + 1650}{2 ( - 915 )} : - 1

x = \frac{- ( - 180 ) - 1650}{2 ( - 915 )} : \frac{49}{61}

The solutions to the quadratic equation are:

x = - 1, x = \frac{49}{61}

x^{2} - 16 x + 48 = 9

y, 9 x^{2} - 4 y^{2} - 36 x - 16 y + 20 = 0

(x + 6)^{2} - 32 = 0

k^{2} + 5 k = - 6

x^{2} + 63 = 16 x

What are the solutions to the equation -91.5x^2-18x+73.5=0 ?
The solutions to the equation -91.5x^2-18x+73.5=0 are x=-1,x= 49/61
Find the zeros of -91.5x^2-18x+73.5=0
The zeros of -91.5x^2-18x+73.5=0 are x=-1,x= 49/61