What are the solutions to the equation u^2=19u ?

The solutions to the equation u^2=19u are u=19,u=0

Find the zeros of u^2=19u

The zeros of u^2=19u are u=19,u=0

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u^{2} = 19 u

u = 19, u = 0

Solution steps

u^{2} = 19 u

Move

19 u

to the left side

u^{2} - 19 u = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 19 ) \pm ( - 19 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 19)^{2} - 4 \cdot 1 \cdot 0 = 19

u_{1, 2} = \frac{- ( - 19 ) \pm 19}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- ( - 19 ) + 19}{2 \cdot 1}, u_{2} = \frac{- ( - 19 ) - 19}{2 \cdot 1}

u = \frac{- ( - 19 ) + 19}{2 \cdot 1} : 19

u = \frac{- ( - 19 ) - 19}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

u = 19, u = 0

x^{2} - x - 4

y, 7 x^{2} - 63 x y + 13 y^{2} - 16 = 0

\frac{1}{2} x^{2} - 5 = 13

1 + \frac{5}{6} x + \frac{1}{6} x^{2} = 0

5 \cdot (- \frac{x ^{2}}{1} + 2 x + 2) = 1

What are the solutions to the equation u^2=19u ?
The solutions to the equation u^2=19u are u=19,u=0
Find the zeros of u^2=19u
The zeros of u^2=19u are u=19,u=0