What are the solutions to the equation 5*(-(x^2)/1+2x+2)=1 ?

The solutions to the equation 5*(-(x^2)/1+2x+2)=1 are x=-(-5+sqrt(70))/5 ,x=(5+sqrt(70))/5

Find the zeros of 5*(-(x^2)/1+2x+2)=1

The zeros of 5*(-(x^2)/1+2x+2)=1 are x=-(-5+sqrt(70))/5 ,x=(5+sqrt(70))/5

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5 \cdot (- \frac{x ^{2}}{1} + 2 x + 2) = 1

x = - \frac{- 5 + 70}{5}, x = \frac{5 + 70}{5}

Decimal Notation

x = - 0.67332 \dots, x = 2.67332 \dots

Solution steps

5 (- \frac{x ^{2}}{1} + 2 x + 2) = 1

Expand

5 (- \frac{x ^{2}}{1} + 2 x + 2) : - 5 x^{2} + 10 x + 10

- 5 x^{2} + 10 x + 10 = 1

Move

1

to the left side

- 5 x^{2} + 10 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 ( - 5 ) \cdot 9}{2 ( - 5 )}

1 0^{2} - 4 (- 5) \cdot 9 = 270

x_{1, 2} = \frac{- 10 \pm 2 70}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 10 + 2 70}{2 ( - 5 )}, x_{2} = \frac{- 10 - 2 70}{2 ( - 5 )}

x = \frac{- 10 + 2 70}{2 ( - 5 )} : - \frac{- 5 + 70}{5}

x = \frac{- 10 - 2 70}{2 ( - 5 )} : \frac{5 + 70}{5}

The solutions to the quadratic equation are:

x = - \frac{- 5 + 70}{5}, x = \frac{5 + 70}{5}

x, 2 x^{2} - 32 x + 128 = 0

(2 x - 4)^{2} = 9

x^{2} - 4 = - 7

25 x^{2} - 4 = 0

z^{2} + 4 z

What are the solutions to the equation 5*(-(x^2)/1+2x+2)=1 ?
The solutions to the equation 5*(-(x^2)/1+2x+2)=1 are x=-(-5+sqrt(70))/5 ,x=(5+sqrt(70))/5
Find the zeros of 5*(-(x^2)/1+2x+2)=1
The zeros of 5*(-(x^2)/1+2x+2)=1 are x=-(-5+sqrt(70))/5 ,x=(5+sqrt(70))/5