What are the solutions to the equation 1+5/6 x+1/6 x^2=0 ?

The solutions to the equation 1+5/6 x+1/6 x^2=0 are x=-2,x=-3

Find the zeros of 1+5/6 x+1/6 x^2=0

The zeros of 1+5/6 x+1/6 x^2=0 are x=-2,x=-3

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1 + \frac{5}{6} x + \frac{1}{6} x^{2} = 0

x = - 2, x = - 3

Solution steps

1 + \frac{5}{6} x + \frac{1}{6} x^{2} = 0

Multiply both sides by

6

x^{2} + 5 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 6 = 1

x_{1, 2} = \frac{- 5 \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 1}{2 \cdot 1}, x_{2} = \frac{- 5 - 1}{2 \cdot 1}

x = \frac{- 5 + 1}{2 \cdot 1} : - 2

x = \frac{- 5 - 1}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = - 2, x = - 3

5 \cdot (- \frac{x ^{2}}{1} + 2 x + 2) = 1

x, 2 x^{2} - 32 x + 128 = 0

(2 x - 4)^{2} = 9

x^{2} - 4 = - 7

25 x^{2} - 4 = 0

What are the solutions to the equation 1+5/6 x+1/6 x^2=0 ?
The solutions to the equation 1+5/6 x+1/6 x^2=0 are x=-2,x=-3
Find the zeros of 1+5/6 x+1/6 x^2=0
The zeros of 1+5/6 x+1/6 x^2=0 are x=-2,x=-3