What are the solutions to the equation x^2-14x=49 ?

The solutions to the equation x^2-14x=49 are x=7(1+sqrt(2)),x=7(1-sqrt(2))

Find the zeros of x^2-14x=49

The zeros of x^2-14x=49 are x=7(1+sqrt(2)),x=7(1-sqrt(2))

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x^{2} - 14 x = 49

x = 7 (1 + 2), x = 7 (1 - 2)

Decimal Notation

x = 16.89949 \dots, x = - 2.89949 \dots

Solution steps

x^{2} - 14 x = 49

Move

49

to the left side

x^{2} - 14 x - 49 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot ( - 49 )}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot (- 49) = 142

x_{1, 2} = \frac{- ( - 14 ) \pm 14 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 14 2}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 14 2}{2 \cdot 1}

x = \frac{- ( - 14 ) + 14 2}{2 \cdot 1} : 7 (1 + 2)

x = \frac{- ( - 14 ) - 14 2}{2 \cdot 1} : 7 (1 - 2)

The solutions to the quadratic equation are:

x = 7 (1 + 2), x = 7 (1 - 2)

3 x^{2} + 24 x + 40 = 0

- 2 - 3 (x - 5)^{2} = - 29

(2 x - 1)^{2} - 16 = 9

x^{2} - x = 380

6 x^{2} - 18 x - 24 = 74

What are the solutions to the equation x^2-14x=49 ?
The solutions to the equation x^2-14x=49 are x=7(1+sqrt(2)),x=7(1-sqrt(2))
Find the zeros of x^2-14x=49
The zeros of x^2-14x=49 are x=7(1+sqrt(2)),x=7(1-sqrt(2))