What are the solutions to the equation roots x^2+6x+58=0 ?

The solutions to the equation roots x^2+6x+58=0 are x=-3+7i,x=-3-7i

Find the zeros of roots x^2+6x+58=0

The zeros of roots x^2+6x+58=0 are x=-3+7i,x=-3-7i

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roots

x^{2} + 6 x + 58 = 0

x = - 3 + 7 i, x = - 3 - 7 i

Solution steps

x^{2} + 6 x + 58 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 58}{2 \cdot 1}

Simplify

6^{2} - 4 \cdot 1 \cdot 58 : 14 i

x_{1, 2} = \frac{- 6 \pm 14 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 14 i}{2 \cdot 1}, x_{2} = \frac{- 6 - 14 i}{2 \cdot 1}

x = \frac{- 6 + 14 i}{2 \cdot 1} : - 3 + 7 i

x = \frac{- 6 - 14 i}{2 \cdot 1} : - 3 - 7 i

The solutions to the quadratic equation are:

x = - 3 + 7 i, x = - 3 - 7 i

t, d = v t + \frac{a t ^{2}}{2}

6 x^{2} + 14 = - 25 x

- 16 x^{2} + 6 x + 22 = 5

36 = 12 x - x^{2}

x^{2} - 6 x - 16

What are the solutions to the equation roots x^2+6x+58=0 ?
The solutions to the equation roots x^2+6x+58=0 are x=-3+7i,x=-3-7i
Find the zeros of roots x^2+6x+58=0
The zeros of roots x^2+6x+58=0 are x=-3+7i,x=-3-7i