What are the solutions to the equation -16x^2+6x+22=5 ?

The solutions to the equation -16x^2+6x+22=5 are x=-(-3+sqrt(281))/(16),x=(3+sqrt(281))/(16)

Find the zeros of -16x^2+6x+22=5

The zeros of -16x^2+6x+22=5 are x=-(-3+sqrt(281))/(16),x=(3+sqrt(281))/(16)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 16 x^{2} + 6 x + 22 = 5

x = - \frac{- 3 + 281}{16}, x = \frac{3 + 281}{16}

Decimal Notation

x = - 0.86019 \dots, x = 1.23519 \dots

Solution steps

- 16 x^{2} + 6 x + 22 = 5

Move

5

to the left side

- 16 x^{2} + 6 x + 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 16 ) \cdot 17}{2 ( - 16 )}

6^{2} - 4 (- 16) \cdot 17 = 2281

x_{1, 2} = \frac{- 6 \pm 2 281}{2 ( - 16 )}

Separate the solutions

x_{1} = \frac{- 6 + 2 281}{2 ( - 16 )}, x_{2} = \frac{- 6 - 2 281}{2 ( - 16 )}

x = \frac{- 6 + 2 281}{2 ( - 16 )} : - \frac{- 3 + 281}{16}

x = \frac{- 6 - 2 281}{2 ( - 16 )} : \frac{3 + 281}{16}

The solutions to the quadratic equation are:

x = - \frac{- 3 + 281}{16}, x = \frac{3 + 281}{16}

36 = 12 x - x^{2}

x^{2} - 6 x - 16

0 = - 4.9 t^{2} - 44.1 t + 176.4

- 16 t^{2} + 34 t + 42 = 0

x^{2} - 8 (x + 3) = + 4 x - 45

What are the solutions to the equation -16x^2+6x+22=5 ?
The solutions to the equation -16x^2+6x+22=5 are x=-(-3+sqrt(281))/(16),x=(3+sqrt(281))/(16)
Find the zeros of -16x^2+6x+22=5
The zeros of -16x^2+6x+22=5 are x=-(-3+sqrt(281))/(16),x=(3+sqrt(281))/(16)