What are the solutions to the equation factor x^2-8x+8=-4 ?

The solutions to the equation factor x^2-8x+8=-4 are x=2,x=6

Find the zeros of factor x^2-8x+8=-4

The zeros of factor x^2-8x+8=-4 are x=2,x=6

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x^{2} - 8 x + 8 = - 4

x = 2, x = 6

Solution steps

x^{2} - 8 x + 8 = - 4

Move

4

to the left side

x^{2} - 8 x + 12 = 0

Factor

x^{2} - 8 x + 12 : (x - 2) (x - 6)

(x - 2) (x - 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x - 6 = 0

Solve

x - 2 = 0 : x = 2

Solve

x - 6 = 0 : x = 6

The solutions to the quadratic equation are:

x = 2, x = 6

4 x^{2} + 32 x + 73 = 0

- 6 x^{2} + 60 x - 96 = 0

x^{2} + 18 x + 27 = 8 x + 3

12 a^{2} - 22 a - 5 = - 5 a

9 x^{2} + 6 x + 5

What are the solutions to the equation factor x^2-8x+8=-4 ?
The solutions to the equation factor x^2-8x+8=-4 are x=2,x=6
Find the zeros of factor x^2-8x+8=-4
The zeros of factor x^2-8x+8=-4 are x=2,x=6