What are the solutions to the equation 5x^2-13x+6=x^2 ?

The solutions to the equation 5x^2-13x+6=x^2 are x=(13+sqrt(73))/8 ,x=(13-sqrt(73))/8

Find the zeros of 5x^2-13x+6=x^2

The zeros of 5x^2-13x+6=x^2 are x=(13+sqrt(73))/8 ,x=(13-sqrt(73))/8

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5 x^{2} - 13 x + 6 = x^{2}

x = \frac{13 + 73}{8}, x = \frac{13 - 73}{8}

Decimal Notation

x = 2.69300 \dots, x = 0.55699 \dots

Solution steps

5 x^{2} - 13 x + 6 = x^{2}

Move

x^{2}

to the left side

4 x^{2} - 13 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 4 \cdot 6}{2 \cdot 4}

(- 13)^{2} - 4 \cdot 4 \cdot 6 = 73

x_{1, 2} = \frac{- ( - 13 ) \pm 73}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 73}{2 \cdot 4}, x_{2} = \frac{- ( - 13 ) - 73}{2 \cdot 4}

x = \frac{- ( - 13 ) + 73}{2 \cdot 4} : \frac{13 + 73}{8}

x = \frac{- ( - 13 ) - 73}{2 \cdot 4} : \frac{13 - 73}{8}

The solutions to the quadratic equation are:

x = \frac{13 + 73}{8}, x = \frac{13 - 73}{8}

m^{2} = \frac{24}{3}, m^{1} = 8

3 n^{2} - n - 4 = 0

x^{2} + 7 - 8 x = 0

2 (x - 1)^{2} = 10 x

3 x^{2} + 90 = 36 x

What are the solutions to the equation 5x^2-13x+6=x^2 ?
The solutions to the equation 5x^2-13x+6=x^2 are x=(13+sqrt(73))/8 ,x=(13-sqrt(73))/8
Find the zeros of 5x^2-13x+6=x^2
The zeros of 5x^2-13x+6=x^2 are x=(13+sqrt(73))/8 ,x=(13-sqrt(73))/8