What are the solutions to the equation factor 4x^2+3x+3=4 ?

The solutions to the equation factor 4x^2+3x+3=4 are x= 1/4 ,x=-1

Find the zeros of factor 4x^2+3x+3=4

The zeros of factor 4x^2+3x+3=4 are x= 1/4 ,x=-1

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4 x^{2} + 3 x + 3 = 4

x = \frac{1}{4}, x = - 1

Decimal Notation

x = 0.25, x = - 1

Solution steps

4 x^{2} + 3 x + 3 = 4

Move

4

to the left side

4 x^{2} + 3 x - 1 = 0

Factor

4 x^{2} + 3 x - 1 : (4 x - 1) (x + 1)

(4 x - 1) (x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

4 x - 1 = 0 or x + 1 = 0

Solve

4 x - 1 = 0 : x = \frac{1}{4}

Solve

x + 1 = 0 : x = - 1

The solutions to the quadratic equation are:

x = \frac{1}{4}, x = - 1

5 x^{2} + 8 x + 9 = 0

x^{2} - 6 x - 8 = - 1

x^{2} + 32 x + 250 = 0

3 X^{2} - 5 X + 2 = 0

0 = - 16 x^{2} + 8 x + 8

What are the solutions to the equation factor 4x^2+3x+3=4 ?
The solutions to the equation factor 4x^2+3x+3=4 are x= 1/4 ,x=-1
Find the zeros of factor 4x^2+3x+3=4
The zeros of factor 4x^2+3x+3=4 are x= 1/4 ,x=-1