What are the solutions to the equation x^2+32x+250=0 ?

The solutions to the equation x^2+32x+250=0 are x=-16+sqrt(6),x=-16-sqrt(6)

Find the zeros of x^2+32x+250=0

The zeros of x^2+32x+250=0 are x=-16+sqrt(6),x=-16-sqrt(6)

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x^{2} + 32 x + 250 = 0

x = - 16 + 6, x = - 16 - 6

Decimal Notation

x = - 13.55051 \dots, x = - 18.44948 \dots

Solution steps

x^{2} + 32 x + 250 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 32 \pm 3 2 ^{2} - 4 \cdot 1 \cdot 250}{2 \cdot 1}

3 2^{2} - 4 \cdot 1 \cdot 250 = 26

x_{1, 2} = \frac{- 32 \pm 2 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 32 + 2 6}{2 \cdot 1}, x_{2} = \frac{- 32 - 2 6}{2 \cdot 1}

x = \frac{- 32 + 2 6}{2 \cdot 1} : - 16 + 6

x = \frac{- 32 - 2 6}{2 \cdot 1} : - 16 - 6

The solutions to the quadratic equation are:

x = - 16 + 6, x = - 16 - 6

3 X^{2} - 5 X + 2 = 0

0 = - 16 x^{2} + 8 x + 8

0 = - x^{2} + 4 x - 1

(x + 4) (x - 4) - (x - 2)^{2} = x (x - 5)

x = - x^{2} + 1000 x

What are the solutions to the equation x^2+32x+250=0 ?
The solutions to the equation x^2+32x+250=0 are x=-16+sqrt(6),x=-16-sqrt(6)
Find the zeros of x^2+32x+250=0
The zeros of x^2+32x+250=0 are x=-16+sqrt(6),x=-16-sqrt(6)