What are the solutions to the equation 3x^2+6x+3=0 ?

The solutions to the equation 3x^2+6x+3=0 are x=-1

Find the zeros of 3x^2+6x+3=0

The zeros of 3x^2+6x+3=0 are x=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} + 6 x + 3 = 0

x = - 1

Solution steps

3 x^{2} + 6 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 \cdot 3}{2 \cdot 3}

6^{2} - 4 \cdot 3 \cdot 3 = 0

x_{1, 2} = \frac{- 6 \pm 0}{2 \cdot 3}

x = \frac{- 6}{2 \cdot 3}

\frac{- 6}{2 \cdot 3} = - 1

x = - 1

The solution to the quadratic equation is:

x = - 1

- 16 x^{2} = 20 x^{2} + 24 x + 5

10 x^{2} - 27 x + 18 = 0

(- 2 x + 7) (x - 1) = 3

n^{2} + 3 n = 10

s, (s + 4)^{2} + 9 = 0

What are the solutions to the equation 3x^2+6x+3=0 ?
The solutions to the equation 3x^2+6x+3=0 are x=-1
Find the zeros of 3x^2+6x+3=0
The zeros of 3x^2+6x+3=0 are x=-1