What are the solutions to the equation roots x^2+4x+20=0 ?

The solutions to the equation roots x^2+4x+20=0 are x=-2+4i,x=-2-4i

Find the zeros of roots x^2+4x+20=0

The zeros of roots x^2+4x+20=0 are x=-2+4i,x=-2-4i

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roots

x^{2} + 4 x + 20 = 0

x = - 2 + 4 i, x = - 2 - 4 i

Solution steps

x^{2} + 4 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 20 : 8 i

x_{1, 2} = \frac{- 4 \pm 8 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 8 i}{2 \cdot 1}, x_{2} = \frac{- 4 - 8 i}{2 \cdot 1}

x = \frac{- 4 + 8 i}{2 \cdot 1} : - 2 + 4 i

x = \frac{- 4 - 8 i}{2 \cdot 1} : - 2 - 4 i

The solutions to the quadratic equation are:

x = - 2 + 4 i, x = - 2 - 4 i

- 20 x^{2} = 4 x

- 3 x^{2} - 7 x + 5

60 x^{2} - 180 x = 0

f, f^{- 1} (x) = x^{2} - 2

f, f^{- 1} (x) = x^{2} - 4

What are the solutions to the equation roots x^2+4x+20=0 ?
The solutions to the equation roots x^2+4x+20=0 are x=-2+4i,x=-2-4i
Find the zeros of roots x^2+4x+20=0
The zeros of roots x^2+4x+20=0 are x=-2+4i,x=-2-4i