What are the solutions to the equation -2x^2-12x-8=0 ?

The solutions to the equation -2x^2-12x-8=0 are x=-3-sqrt(5),x=-3+sqrt(5)

Find the zeros of -2x^2-12x-8=0

The zeros of -2x^2-12x-8=0 are x=-3-sqrt(5),x=-3+sqrt(5)

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- 2 x^{2} - 12 x - 8 = 0

x = - 3 - 5, x = - 3 + 5

Decimal Notation

x = - 5.23606 \dots, x = - 0.76393 \dots

Solution steps

- 2 x^{2} - 12 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 ( - 2 ) ( - 8 )}{2 ( - 2 )}

(- 12)^{2} - 4 (- 2) (- 8) = 45

x_{1, 2} = \frac{- ( - 12 ) \pm 4 5}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 4 5}{2 ( - 2 )}, x_{2} = \frac{- ( - 12 ) - 4 5}{2 ( - 2 )}

x = \frac{- ( - 12 ) + 4 5}{2 ( - 2 )} : - 3 - 5

x = \frac{- ( - 12 ) - 4 5}{2 ( - 2 )} : - 3 + 5

The solutions to the quadratic equation are:

x = - 3 - 5, x = - 3 + 5

(3 x - 7)^{2} + 4 = 29

s^{2} - 2 s - 14 = 0

3 x^{2} + 12 x + 20 = 0

- 5 x^{2} + 35 x - 50 = - 200

4 x^{2} = (x + 1)^{2} + b

What are the solutions to the equation -2x^2-12x-8=0 ?
The solutions to the equation -2x^2-12x-8=0 are x=-3-sqrt(5),x=-3+sqrt(5)
Find the zeros of -2x^2-12x-8=0
The zeros of -2x^2-12x-8=0 are x=-3-sqrt(5),x=-3+sqrt(5)