What are the solutions to the equation (3x-7)^2+4=29 ?

The solutions to the equation (3x-7)^2+4=29 are x=4,x= 2/3

Find the zeros of (3x-7)^2+4=29

The zeros of (3x-7)^2+4=29 are x=4,x= 2/3

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(3 x - 7)^{2} + 4 = 29

x = 4, x = \frac{2}{3}

Decimal Notation

x = 4, x = 0.66666 \dots

Solution steps

(3 x - 7)^{2} + 4 = 29

Move

4

to the right side

(3 x - 7)^{2} = 25

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x - 7 = 25 : x = 4

Solve

3 x - 7 = - 25 : x = \frac{2}{3}

The solutions to the quadratic equation are:

x = 4, x = \frac{2}{3}

s^{2} - 2 s - 14 = 0

3 x^{2} + 12 x + 20 = 0

- 5 x^{2} + 35 x - 50 = - 200

4 x^{2} = (x + 1)^{2} + b

y, (x - 1)^{2} + y^{2} = 0

What are the solutions to the equation (3x-7)^2+4=29 ?
The solutions to the equation (3x-7)^2+4=29 are x=4,x= 2/3
Find the zeros of (3x-7)^2+4=29
The zeros of (3x-7)^2+4=29 are x=4,x= 2/3