What are the solutions to the equation 3x^2+12x+20=0 ?

The solutions to the equation 3x^2+12x+20=0 are x=-2+i(2sqrt(6))/3 ,x=-2-i(2sqrt(6))/3

Find the zeros of 3x^2+12x+20=0

The zeros of 3x^2+12x+20=0 are x=-2+i(2sqrt(6))/3 ,x=-2-i(2sqrt(6))/3

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3 x^{2} + 12 x + 20 = 0

x = - 2 + i \frac{2 6}{3}, x = - 2 - i \frac{2 6}{3}

Solution steps

3 x^{2} + 12 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 3 \cdot 20}{2 \cdot 3}

Simplify

1 2^{2} - 4 \cdot 3 \cdot 20 : 46 i

x_{1, 2} = \frac{- 12 \pm 4 6 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 12 + 4 6 i}{2 \cdot 3}, x_{2} = \frac{- 12 - 4 6 i}{2 \cdot 3}

x = \frac{- 12 + 4 6 i}{2 \cdot 3} : - 2 + i \frac{2 6}{3}

x = \frac{- 12 - 4 6 i}{2 \cdot 3} : - 2 - i \frac{2 6}{3}

The solutions to the quadratic equation are:

x = - 2 + i \frac{2 6}{3}, x = - 2 - i \frac{2 6}{3}

- 5 x^{2} + 35 x - 50 = - 200

4 x^{2} = (x + 1)^{2} + b

y, (x - 1)^{2} + y^{2} = 0

x^{2} + 16 x + 71

x^{2} - 109 = - 8 x

What are the solutions to the equation 3x^2+12x+20=0 ?
The solutions to the equation 3x^2+12x+20=0 are x=-2+i(2sqrt(6))/3 ,x=-2-i(2sqrt(6))/3
Find the zeros of 3x^2+12x+20=0
The zeros of 3x^2+12x+20=0 are x=-2+i(2sqrt(6))/3 ,x=-2-i(2sqrt(6))/3