What is the answer to solvefor y,x= 1/(y-3) ?

The answer to solvefor y,x= 1/(y-3) is y= 1/x+3;\quad x\ne 0

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solvefor y,x= 1/(y-3)

solve for

y, x = \frac{1}{y - 3}

y = \frac{1}{x} + 3; x \neq = 0

Solution steps

x = \frac{1}{y - 3}

Multiply both sides by

y - 3

x (y - 3) = 1

Divide both sides by

x; x \neq = 0

y - 3 = \frac{1}{x}; x \neq = 0

Move

3

to the right side

y = \frac{1}{x} + 3; x \neq = 0

y, x = \frac{1}{y - 2}

y, \frac{3 y - x}{3 - 2 x} = - 4

\frac{2}{x + 1} - \frac{1}{3} = \frac{1}{4 x + 4}

\frac{2 x + 7}{5 - x} = \frac{8}{3}

\frac{s ^{6} - n ^{9}}{s ^{6} - n ^{6}}

What is the answer to solvefor y,x= 1/(y-3) ?
The answer to solvefor y,x= 1/(y-3) is y= 1/x+3;\quad x\ne 0